Content code
m1320
Slug (identifier)
forms-of-a-straight-line-equation
Grades
Secondary III
Secondary IV
Topic
Mathematics
Content
Contenu
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A linear equation can be written in three different forms: functional, general, and symmetrical.

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Comparative Table of the Three Forms of Linear Equations:

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Equation Form

Slope

Y-intercept

X-intercept

Functional
|y = mx + b|

|m|

|b|

|\dfrac{-b}{m}|

General
|Ax + By + C = 0|

|\displaystyle \frac{-A}{B}|

|\displaystyle \frac{-C}{B}|

|\dfrac{-C}{A}|

Symmetrical
|\displaystyle \frac{x}{a} + \frac{y}{b} = 1|

|\displaystyle \frac{-b}{a}|

|b|

|a|

Title (level 2)
The Functional Form of a Linear Equation
Title slug (identifier)
functional-form
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The functional form of a linear equation is: |y=mx + b|, where |m| is the slope of the line and |b| is its y-intercept (initial value).

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The linear functions below are expressed in functional form:

|y = 2x + 3|, where |m = 2| and |b = 3|

|y = -3x - 6|, where |m = -3| and |b = -6|

|y = \frac{1}{2}x + \frac{3}{4}|, where |m = \frac{1}{2}| and |b = \frac{3}{4}|

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The functional form makes it possible to express all the straight lines except the vertical lines of the form |x = constant|. In this form, the slope |m| is undefined since it is impossible to divide by 0, which is the case when calculating the slope of a vertical line.

Title (level 2)
The General Form of a Linear Equation
Title slug (identifier)
general-form
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The general form of a linear function is:

|Ax + By + C = 0|,

where

|A| and |B| must not be equal to |0| at the same time.
In general, |A,| |B|, and |C| are whole numbers and |A| is positive.

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Contrary to the functional form, it is not possible to use the general form of a straight line equation to directly find the slope and the y-intercept’s value. Rather, they should be calculated from the coefficients A, B, and C. Thus:

  • The slope of the equation is calculated with the formula |m=\dfrac{-A}{B}.|

  • The y-intercept is calculated with the formula |b=\dfrac{-C}{B}.|

  • The x-intercept is calculated with the formula |a=\dfrac{-C}{A}.|

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The general form of a linear equation makes it possible to express all types of straight lines, i.e., vertical, horizontal, increasing, or decreasing.

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The linear function equations below are in the general form:

|2x - 3y + 7 = 0|

|x + 6y - 9 = 0|

|-3x + 4 = 0 \Rightarrow| Vertical line

|6y - 3 = 0 \Rightarrow| Horizontal line

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The linear function below is expressed in a form that resembles the general form, but the coefficient of the variable |x| is not an integer and is not positive.

|\displaystyle \frac{-x}{2} + 3y - 7 = 0|

It is possible to multiply all the terms by -2 to eliminate the fraction and the parameter’s negative sign |A| to get the general form.

|\displaystyle -2\times \left(\frac{-x}{2} + 3y - 7 = 0 \right)|

The result is:

|x - 6y + 14 = 0|.

Title (level 2)
The Symmetrical Form of a Linear Equation
Title slug (identifier)
symmetrical-form
Contenu
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The symmetrical form of a linear equation is:

|\displaystyle \frac{x}{a}+\frac{y}{b}=1|

where
|a| is the x-intercept (zero) and
|b| is the intercept (the initial value).

The |x| and the |y| must be the only elements present in their respective fraction’s numerator.

It is also important for |a\neq 0| and |b\neq 0| since dividing by 0 is undefined.

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Contrary to the functional form of a linear equation, it is not possible to use the symmetrical form to directly find the value of the slope. Rather, it is calculated using the following formula:

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The slope can be calculated with the following formula: |\displaystyle m=\frac{-b}{a}|.

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The following linear function is in symmetrical form:

|\displaystyle \frac{x}{3}+\frac{y}{4}=1|.

The following linear function is not in symmetrical form:
|\displaystyle \frac{2x}{3}-\frac{7y}{4}=1|.

However, it is possible to express it in symmetric form by inverting the coefficients of |x| and |y| and placing them in the denominator:

|\displaystyle \frac{x}{(\frac{3}{2})}+ \frac{y}{(\frac{-​4}{7})}=1|.

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The symmetrical form makes it possible to express the majority of straight lines equations with these three exceptions:

  • Vertical lines (there would be no y-intercept |b|).

  • Horizontal lines (there would be no x-intercept |a|).

  • Straight lines passing through the origin |(0,0)| (it is impossible to divide by 0).

Title (level 2)
How to Switch from One Form to Another
Title slug (identifier)
switch-from-one-form-to-another
Contenu
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It is possible to find the answer using all three forms of linear equations. To demonstrate how to switch from one form to another, use the same example for the three forms of equation.

Title (level 3)
From Functional Form to the General Form
Title slug (identifier)
functional-form-general-form
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To switch to the general form from the functional form of the equation |\displaystyle y = \frac{4}{5}x - 4|, make the equation equal to 0 and ensure the coefficients are whole numbers.

  1. Multiply the two sides of the equality by 5 to eliminate any fractions, incorporate integer coefficients, and ensure the |A| is positive. ||\begin{align}\displaystyle 5\ (y) &=5\ \left(\frac{4}{5}x-4 \right)\\5y &=4x-20 \end{align}||

  2. Move the |5y| to the other side of the equation to make the whole equality zero.
    ||0 = 4x – 5y – 20||

Title (level 3)
From General to Symmetrical Form
Title slug (identifier)
general-form-symmetrical-form
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To switch to the symmetrical form from the general form |0 = 4x – 5y – 20|, transform the equation so it is equal to |1|.

  1. Move the |20| to the other side of equality.
    ||20 = 4x -5y||

  2. The equality must be equal to |1|. Thus, divide the terms by |20|.
    ||\displaystyle \frac{20}{20} = \frac{4}{20}x - \frac{5}{20}y||

  3. After simplifying, the result is:
    ||\displaystyle 1 = \frac{x}{5} - \frac{y}{4}||

    Thus, we learn the x-intercept of the line is |5| and its y-intercept is |\text{-}4|.

Title (level 3)
From Functional Form to Symmetrical Form
Title slug (identifier)
functional-form-symmetrical-form
Content
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To switch to symmetrical form from functional form |\displaystyle y = \frac{4}{5}x - 4|, place the variables on the same side of the equality and ensure that the equation is equal to |1|.

  1. Move the |\frac{4}{5}x| to the other side of the equality.
    ||-\dfrac{4}{5}x+y = -4||

  2. The equality must be equal to |1|. Thus, divide all the terms by |\text{-}4|.
    ||\displaystyle \frac{\frac{-4}{5}x}{-4} + \frac{y}{-4} = \frac{-4}{-4}||

  3. After simplifying, the result is:
    ||\displaystyle \frac{x}{5} - \frac{y}{4}=1||

Title (level 3)
From Symmetrical Form to General Form
Title slug (identifier)
symmetrical-form-general-form
Content
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To switch to the general form from the symmetrical form |\displaystyle \frac{x}{5} - \frac{y}{4}=1|, move all the terms to the same side of the equality and ensure there are no more fractions.

  1. Move the |1| to the other side of the equality.
    ||\displaystyle \frac{x}{5} - \frac{y}{4}-1=0||

  2. Multiply all the terms by the LCM of A and B: |\text{LCM}(5,4)=20|
    ||\begin{align}\displaystyle 20\left(\frac{x}{5}\right) + 20 \left(-\frac{y}{4}\right)+20(-1)&=20(0)\\ 4x \phantom{)+20(}-5y\phantom{+20}-20\phantom{())}&=\phantom{()}0 \end{align}||

Title (level 3)
From General Form to Functional Form
Title slug (identifier)
general-form-functional-form
Content
Corps

To switch to functional form from the general form |0 = 4x – 5y – 20|, isolate the variable |y|.

  1. Move the |4x| and the |20| to the other side of equality.
    ||-5y=-4x+20||

  2. Divide all the terms by the coefficient of |y|.
    ||\displaystyle \frac{-5y}{-5}=\frac{-4x}{-5}+\frac{20}{-5}||

  3. After simplifying, the result is:
    ||y=\dfrac{4}{5}x-4||

Title (level 3)
From Symmetrical Form to Functional Form
Title slug (identifier)
symmetrical-form-functional-form
Content
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To switch to the functional form from the symmetrical form |\displaystyle \frac{x}{5} - \frac{y}{4}=1|, isolate the variable |y|.

  1. Move the |\frac{x}{5}| to the other side of the equality.
    ||\displaystyle - \frac{y}{4}=-\frac{x}{5}+1||

  2. Multiply by -4 (both sides of the equality) to isolate |y|.
    ||\begin{align}\displaystyle -4\left(- \frac{y}{4}\right)&=-4\left(-\frac{x}{5}+1\right)\\y\ \ \ \ &=\ \ \ \ \dfrac{4}{5}x\ \ -\ \ 4 \end{align}||

Title (level 2)
Exercise
Title slug (identifier)
exercise
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