Content code
p1015
Slug (identifier)
impulse-and-momentum
Parent content
Grades
Secondary V
Topic
Physics
Tags
quantity
movements
transmitted
objects
speed
mass
momentum
impulse
elastic collisions
inelastic collisions
Content
Title (level 2)
Momentum
Title slug (identifier)
momentum
Contenu
Content
Corps

Momentum is a physical quantity of motion associated with the mass and speed of an object.

Corps

It is used to study the behavior of objects that collide with each other. As with energy, momentum must be the same at the beginning and end of a problem.

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Corps

To determine the momentum of an object, the following equation must be used:


|\overrightarrow{p} = m \cdot \overrightarrow{v}|
where
|\overrightarrow{p}| represents the object's momentum |\text {kg}\cdot \text {m/s}|
|m| represents the mass of the object |\text {kg}|
|\overrightarrow{v}| represents the velocity of the object |\text {m/s}|

Title (level 2)
Types of collision
Title slug (identifier)
types-of-collision
Contenu
Corps

Collisions are classified into three categories.

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Corps

An inelastic collision is a collision between two objects in which the momentum is conserved, but the kinetic energy is not.

A perfectly inelastic collision is one in which the two objects remain attached to each other.

An elastic collision is a collision between two objects in which both the momentum and kinetic energy are conserved.

Content
Corps

A cannon on wheels that weighs |2000 \: \text {kg}| fires a |25 \: \text {kg}| ball to the right.  If the barrel recoils at a rate of |2 \: \text {m/s}| (to the left), what is the speed of the cannonball?

Horizontally, the sum of the momentums at the start must equal those at the end.
||\begin{align}
\overrightarrow{p}_{\text{canon}_{i}}+\overrightarrow{p}_{\text{cannonball}_{i}}&=\overrightarrow{p}_{\text{canon}_{f}}+\overrightarrow{p}_{\text{cannonball}_{f}} \\
m \cdot \overrightarrow{v}_{\text{canon}_{i}}+m \cdot \overrightarrow{v}_{\text{cannonball}_{i}}&=m \cdot \overrightarrow{v}_{\text{canon}_{f}}+m \cdot \overrightarrow{v}_{\text{cannonball}_{f}} \\
2000 \: \text {kg} \cdot 0 \: \text {m/s} + 25 \: \text {kg} \cdot 0 \: \text {m/s} &= 2000 \: \text {kg} \cdot (-2 \: \text {m/s}) + 25 \: \text {kg} \cdot \overrightarrow{v}_{cannonball_{f}} \\
0 &= - 4000 + 25 \cdot \overrightarrow{v}_{cannonball_{f}} \\
4000 &= 25 \cdot \overrightarrow{v}_{cannonball_{f}} \\
\overrightarrow{v}_{cannonball_{f}} &= + 160 \: \text {m/s}
\end{align}||

Title (level 2)
Impulse
Title slug (identifier)
impulse
Contenu
Content
Corps

The impulse represents the momentum (or quantity of motion) transmitted to an object.

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To change the momentum of an object, a force must be applied to it over a certain period of time. 

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Corps

The equation for determining the impulse is as follows:
|\overrightarrow{J}=\overrightarrow{F} \cdot \triangle t |
where
|\overrightarrow{J}| represents the transmitted impulse |\text {N} \cdot \text {s}|
|\overrightarrow{F}| represents the net force acting on an object |\text {N}|
|\triangle t | represents the elapsed time |\text {s}|

Corps

Impulse can also be calculated by determining the area under the curve of a graph that represents force in relation to the time elapsed.

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Corps

The force applied to a sled is represented on the graph below. What impulse has been applied to the sled?

Image
Graph
Corps

To calculate the impulse, you need to calculate the area under the curve.
||\begin{align}A = \frac {b \times h}{2} \quad \Rightarrow \quad A &= \frac {70 \: \text {s} \times 300 \: \text {N}}{2} \\
&= 10 \: 500 \: \text {N} \cdot \text {s}
\end{align}||

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Since the impulse varies the momentum, it is possible to link these two variables using a formula.

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Corps

The relationship between impulse and momentum is described by the following equation:
|\overrightarrow{I}=\overrightarrow{p}_{f} - \overrightarrow{p}_{i}|
where
|\overrightarrow{I}| represents the impulse |\text {N} \cdot \text {s}|
|\overrightarrow{p}_{f}| represents the final momentum |\text {kg} \cdot \text {m/s}|
|\overrightarrow{p}_{i}| represents the initial momentum |\text {kg} \cdot \text {m/s}|

 

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Corps

Since both of these quantities of motion (momentum and impulse) are vectors in the previous equation, we will need to subtract the vectors to find the impulse. However, when these two quantities of motion are oriented in the same direction, we can just subtract their vector magnitudes.

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