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m1514
Slug (identifier)
the-area-of-truncated-solids
Grades
Secondary II
Secondary III
Topic
Mathematics
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A truncated solid is a solid that has been cut by a plane where only a portion of the original figure remains. The plane cutting the solid may be parallel to its base or not.

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The following is an illustration of various cones truncated by a plane.

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Cones truncated by a plane that is parallel to the base and a plane that is not parallel to the base
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In the image, we see that the first two cones are created using a plane parallel to the base of the cone. This type of truncated cone will be studied here. 

In the case of the last two cones, the plane is not parallel to the base of the cone. This type of truncated cone will not be studied here. 

Title (level 2)
The Area of a Truncated Solid
Title slug (identifier)
area
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To calculate the area of a truncated solid, it is essential to establish the initial known solids associated with the truncated solid, or to decompose it according to the figures that make it up.

Title (level 3)
Strategy 1: Establish the Initial Known Solids Associated With the Truncated Solid
Title slug (identifier)
strategy-1-associate-the-truncated-solid-with-a-known-initial-solid
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What is the total area of the following truncated cone given that the radius, height and apothem of the original cone associated with it measure 9 cm, 16 cm and 18.36 cm respectively?

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Example of a truncated cone where the total area is sought
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  1. Calculate the area of the bases
    In this case, the bases are two circles which have different radius measurements.

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Small base of the truncated cone where the total area is sought
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||\begin{align} A_\text{small base} &= \pi \color{#333FB1}{r}^2 \\ &= \pi (\color{#333FB1}{5.63})^2 \\ &\approx 99.58\ \text{cm}^2 \end{align}||

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Large base of the truncated cone where the total area is sought.
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||\begin{align} A_\text{large base} &= \pi \color{#333FB1}{r}^2\\ &= \pi (\color{#333FB1}{9})^2 \\ &\approx 254.47\ \text{cm}^2 \end{align}||

||\begin{align} A_\text{bases} &= 99.58 + 254.47 \\ &= 354.05\ \text{cm}^2 \end{align}||

  1. Identify the associated solids
    To help with the rest of the calculations, it is essential to correctly identify the initial known solids. In this case, cones were used to create the solid.

Image
Trunk of the cone, complete (initial) cone and the truncated portion of the initial cone
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  1. Calculate the lateral area
    The measure of the apothem of the truncated portion (figure 3) must be found. We can use subtraction to find it.||\begin{align} a_3 &= a_2 - a_1 \\ &= 18.36 - 6.88 \\ &= 11.48 \ \text{cm} \end{align}||Referring to the solids found in the other steps, we can determine the following. ||\begin{align} A_{L1} &= A_{L2} - A_{L3}\\ &= \pi r_2 a_2 - \pi r_3 a_3 \\ &= \pi (9) (18.36) - \pi (5.63) (11.48) \\ &\approx 316.07 \ \text{cm}^2 \end{align}||

  1. Calculate the total area
    ||\begin{align} A_T &= A_L + A_\text{bases}\\ &\approx 316.07 +354.05\\ &\approx 670.12 \ \text{cm}^2 \end{align}||​

  2. Interpret the answer
    The total area of the truncated cone is approximately |670.12\ \text{cm}^2.|

Title (level 3)
Strategy 2: Decompose the Truncated Solid According to the Figures that Make it Up
Title slug (identifier)
strategy-2-break-down-the-truncated-solid-according-to-the-figures-of-which-it-is-composed
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Ariane wants to wrap a gift that she bought for her little sister. The box, illustrated below, has the form of a truncated pyramid.

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Example of a truncated pyramid where the total area is sought
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What is the minimum surface area of wrapping paper that Ariane will need to wrap the present?

  1. Calculate the area of the bases
    The two bases are rectangles with different measurements.

Image
Small base of the truncated pyramid where the total area is sought
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||\begin{align} A_\text{small base} &= \color{#51b6c2}{b} \times \color{#efc807}{h} \\ &= \color{#51b6c2}{15.17} \times \color{#efc807}{12.28} \\ &\approx 186.29\ \text{cm}^2 \end{align}||

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Large base of the truncated pyramid where the total area is sought
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||\begin{align} A_\text{large base} &= \color{#7cca51}{b} \times \color{#fa7921}{h} \\ &= \color{#7cca51}{21} \times \color{#fa7921}{17} \\ &= 357\ \text{cm}^2 \end{align}||

||\begin{align} A_\text{bases} &= 186.29 + 357 \\ &= 543.29\ \text{cm}^2 \end{align}||

  1. Calculate the lateral area 
    The lateral area is made up of 2 pairs of isosceles trapezoids.

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Small trapezoid, for which the area is sought, that is part of the lateral faces of the truncated pyramid.
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||\begin{align}A_\text{small trapezoid} &= \dfrac{(\color{#fa7921}{B_1}+ \color{#efc807}{b_1}) \times \color{#c58ae1}{h}}{2}\\ &=\dfrac{(\color{#fa7921}{17}+ \color{#efc807}{12.28}) \times \color{#c58ae1}{15}}{2}\\ &= 219.6\ \text{cm}^2\end{align}||

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Large trapezoid, for which the area is sought, that is part of the lateral faces of the truncated pyramid.
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||\begin{align}A_\text{large trapezoid} &= \dfrac{(\color{#7cca51}{B_2}+ \color{#51b6c2}{b_2}) \times \color{#ff55c3}{h}}{2}\\ &=\dfrac{{(\color{#7cca51}{21}+ \color{#51b6c2}{15.17})} \times \color{#ff55c3}{14.9}}{2}\\ &\approx{269.47}\ \text{cm}^2\end{align}||

||\begin{align} A_\text{L} &= {2}\times{A_\text{small trapezoid}} +{2}\times{A_\text{large trapezoid}}  \\ &= {2}\times{219.6} +{2}\times{269.47}\\&= 978.14\ \text{cm}^2 \end{align}||

  1. Calculate the total area
    ||\begin{align} A_T &= A_\text{bases} + A_L\\ &= 543.29 +978.14\\ &= 1\ 521.43 \ \text{cm}^2 \end{align}||​

  2. Interpret the answer
    Ariane will need at least |1\ 521.43\ \text{cm}^2| of wrapping paper to wrap the present for her little sister.

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It is possible to use formulas rather than applying the previous steps. However, the formulas differ according to the type of truncated solid.

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Title
Area Formulas Associated With Truncated Solids
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  1. The lateral area of a truncated cone

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2 columns
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First column
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Truncated cone where the different variables used in the lateral area formula are illustrated
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Taking into account the following variables, we can associate the measure of the lateral area with the following formula:||A_L=\pi(\color{#ec0000}{R}+\color{#333fb1}{r})\color{#3a9a38}{d}\\  \text{where}\\ \begin{align}\color{#ec0000}{R}=&\ \text{radius of the large base}\\ \color{#333fb1}{r}=&\ \text{radius of the small base}\\ \color{#3a9a38}{d}=&\ \text{difference between the apothem of the complete cone}\\&\ \text{and the apothem of the removed cone}\end{align}||This formula only determines the lateral area. To obtain the measure of the total area, it is necessary to add the areas of the two circles that serve as the bases of the truncated cone.

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  1. The lateral area of a regular truncated pyramid

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2 columns
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Truncated pyramid where the different variables used in the lateral area formula are illustrated
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Taking into account the following variables, we can calculate the measure of the lateral area using the following formula:||A_L =\dfrac{(\color{blue}{P}+\color{red}{p})\times\color{green}{d}}{2}\\ \text{where}\\ \begin{align}\color{blue}{P}=&\ \text{Perimeter of the large base}\\ \color{red}{p}=&\ \text{Perimeter of the small base}\\ \color{green}{d}=&\ \text{difference between the apothem of the complete cone}\\&\ \text{and the apothem of the removed cone}\end{align}||​This formula only determines the lateral area. To obtain the measure of the total area, it is necessary to add the areas of each of the bases of the truncated cone.

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Despite the previous formulas, the steps presented in the examples are the most efficient manner of searching for a missing measure in a truncated solid.

Title (level 2)
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